Notes
¢ A vector is a quantity that has direction and magnitude
¢ A scalar is a quantity that can be expressed in terms of its magnitude only
Addition of Vectors: Graphically
First Method
¢ Draw the vectors to scale on graph paper - appropriate for the problem, and in accordance with the following
Ø The beginning of the vector is referred to as the tail, the end of the vector is referred to as the tip
Ø Draw each new vector tail to tail of the previous one. The order is not important; it does not affect the result
¢ The arrow drawn from the tail of the first vector to the tip of the last vector represents the sum of the vectors.
The length is the magnitude of the sum, the direction is as indicated.
Second Method: Parallelogram method - equivalent to the above
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So, the approach discussed above, tail to tip method, works for subtraction with the above understanding
Multiplication of Vectors by a Scalar
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This gives a vector whose magnitude is 1.3 times greater and in the same direction
¢ Graphics methods are often not very precise and not useful for operations in 3 dimensions
¢ A vector can be resolved into and expressed as 2 components, one along the x axis and one along the y axis
¢ Trig relationships
We use the trig functions as discussed here. Assume a right triangle with base = a, height = b, and hypotenuse = c.
Assume the angle between the base and the hypotenuse is referred to as theta (q). With this configuration
sin theta = b/c
cos theta = a/c
tan theta = b/a
¢ Pythagorean Theorem
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in the above, the negative option is not considered
¢ A useful trigonometric identify that follows from the Pythagorean Theorem
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¢ Inverse Tangent
If the tangent of an angle theta is b/a, then the inverse tangent (arc tangent as usually called) is the angle whose tangent is b/a.
It is written theta = arctan(b/a)
General Kinematic Equations for Constant Acceleration
|
x component (horizontal) |
y component (vertical) |
Comments |
|
vx = v0x + axt |
vy = vy0 + ayt |
same except for direction |
|
x = x0 + vx0t + (1/2)axt2 |
y = y0 + vy0t + (1/2)ayt2 |
same except for direction |
|
v2x = v2x0 + 2ax(x - x0) |
v2y = v2y0 + 2ay(y - y0) |
same except for direction |
Kinematic Equations for Projectile Motion
Note that these equations are specific cases of the general equations with stated assumptions
Assuming y is positive upwards, ax = 0, ay = -g
| Horizontal Motion: ax = 0, vx = constant | Vertical Motion: ay = -g |
Comments |
| vx = vx0 | vy = vyo - gt |
ax = 0, ay ≠ 0 |
| x = x0 + vx0t vx = vx0 (same as 1st one-reason not listed in text) |
y = y0 + vy0t - (1/2)gt2 v2y = v2y0 - 2g(y - y0) |
ax = 0, ay ≠ 0, ay = -g ax = 0, square root of both sides |
NOTE: Equations are provided for all review exercises
m into x and y components