Energy in the Simple Harmonic Oscillator
Note the technique (common) for solution
1. Analyze at extreme points and in between
2. Apply conservation law(s)
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Ø PE = elastic potential energy of spring PE =
(1/2)kx2 E = (1/2)mv2 + (1/2)kx2
Ø With no friction, the total mechanical energy remains constant
E = (1/2)m(0)2 + (1/2)kA2 = (1/2)kA2
Ø At the equilibrium point, all of the energy is kinetic
E = (1/2)mv2max
+ (1/2)k(0)2 = (1/2)mv2max E = (1/2)mv2 + (1/2)kx2 = (1/2)kA2
(1/2)mv2max = (1/2)kA2 ð mv2max = kA2 ð
v2max = (k/m)/A2
Ø Finally, from the conservation of total mechanical energy (second equation from top above)
(1/2)mv2 + (1/2)kx2 = (1/2)KA2 and, since we showed that v2max = (k/m)/A2 (previous step above)
v = ± vmax(1 - x2/A2)1/2
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