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Review Exercise 2-2 Answers

Section 1: True-False

 

Indicate whether the following statements are true or false by placing a check mark (P) in the appropriate column.

 

Statement

True

False

The speed of a falling object is not proportional to its mass or weight

P

 

Mass refers to an object’s “quantity of matter”

P

 

Weight is a force

P

 

For a given force, the acceleration of an object is inversely proportional to its mass

P

 

If only one non zero force acts on an object, it cannot have zero acceleration

P

 

Acceleration is the rate of change of velocity

P

 

Acceleration can be negative

P

 

Velocity is the rate of change of distance with time

P

 

Newton’s first law deals with inertia

P

 

Newton’s third law equates force to mass times acceleration

 

P

Velocity is a scalar quantity

 

P

Acceleration and velocity are always in the same direction

 

P

A reference frame attached to an accelerating train is an inertial reference frame

 

P

If the acceleration of an object is 0, there are no forces acting on it

 

P

The normal force is always in the vertical direction

 

P

 

Section 2: Circle the Correct Answer

 

Part b: Circle the correct answer; 1 correct answer for each

 

For each of the following, circle the correct answer. There is only 1 correct answer for each problem.

 

¢  Can work be done on a system if there is no motion?

 

a. Yes, if an outside force is provided.

b. Yes, since motion is only relative.

c. No, since a system which is not moving has no energy.

d. No, because of the way work is defined.

 

¢  A 50-N object was lifted 2.0 m vertically and is being held there.  How much work is being done in holding the box in this position?

 

a. more than 100 J

b.100 J

c. less than 100 J, but more than 0 J

d. 0 J

 

 

¢ A truck weighs twice as much as a car, and is moving at twice the speed of the car.  Which statement is true about the truck's kinetic energy compared to that

   of the car?

 

a. All that can be said is that the truck has more kinetic energy.

b. The truck has twice the kinetic energy of the car.  

c. The truck has 4 times the kinetic energy of the car.

d. The truck has 8 times the kinetic energy of the car.

 

¢  A brick is moving at a speed of 3 m/s and a pebble is moving at a speed of 5 m/s.  If both objects have the same kinetic energy, what is the ratio of the brick's

    mass to the rock's mass?

 

a. 25 to 9

b. 5 to 3

c. 12.5 to 4.5

d. 3 to 5

 

¢  A 4.0-kg mass is moving with speed 2.0 m/s.  A 1.0-kg mass is moving with speed 4.0 m/s.  Both objects encounter the same constant braking force, and are

    brought to rest.  Which object travels the greater distance before stopping?

 

a. the 4.0-kg mass

b. the 1.0-kg mass

c. Both travel the same distance.

d. cannot be determined from the information given

 

¢  You slam on the brakes of your car in a panic, and skid a certain distance on a straight, level road.  If you had been traveling twice as fast, what distance would

    the car have skidded, under the same conditions?

 

a. It would have skidded 4 times farther.

b. It would have skidded twice as far.

c. It would have skidded 1.4 times farther.

d. It is impossible to tell from the information given.

 

¢  A planet of constant mass orbits the Sun in an elliptical orbit.  Neglecting any friction effects, what happens to the planet's kinetic energy?

 

a. It remains constant.

b. It increases continually.

c. It decreases continually.

d. It increases when the planet approaches the Sun, and decreases when it moves farther away.

 

Section 3: Problems

Give answer (not just numbers in an equation) as a number with appropriate units. If p is involved, leave it  in your answer.

 

¢  What is the magnitude of the momentum of a 28-g sparrow flying with a speed of 8.4 m/s?

 

    Simple multiplication using the definition of momentum:

 

         P = mb = (0.028 kg)(8.4 m/s) = 0.24 kg m/s

 

¢  A constant friction force of 25 N acts on a 65-kg skier for 20 s. What is the skier’s change in velocity?

 

    Use Newton's second law in momentum form and solve for delta v

 

    Assume the skier is moving to the right and let this be positive. The friction then acts in a negative direction 

 

       F = ma   gives FD t = m D v    gives   D v = F D t/m

       Using the values given, we have D v = -(25 N)(20 s)/65 kg = -7.7 m/s

 

 

¢  A 1 kg ball is rotating uniformly at the end of a string in a horizontal circle of 1 meter radius. It makes 1 revolution per second.

 

    ð   What is the period, T, of the ball?

 

The period is defined as the time taken for 1 complete revolution

The ball makes 1 rotation about the center in 1 second, therefore it makes 1 revolution in 1 second. So, T = 1 second.

 

    ð  How fast is the ball travelling?

 

Speed = distance/time= 2 p r/T = 2(3.14)(1)/1 = 2p m/s = 6.28 m/s or leave in pi.

 

    ð  What is the centripetal acceleration of the ball?

 

ar = v2/r = (6.28)2/1 = 6.282 m/s2

 

¢  A bike wheel rotates 4 revolutions. How many radians has it rotated?

 

(2 p rad/rotation)x (4 rotations) = 8p radians 

 

¢  A person pulls a 10 kg box over a floor that has a coefficient of friction, Ffr, of 10 N. The box is pulled a straight line, horizontal distance of 20 m by a force of

    30 N acting at an angle of 60 degrees.  Assume that the positive directions are up and to the right.

 

    ð  What is the work done by the friction force, Wfr on the box?

 

Ffrxcosq = (10)(20)cos180 = -200 J

 

    ð  What is the work done by the person, WP, on the box?

 

FPxcosq = (30)(20)cos45 = (30)20)(1/2) = 300 J

 

    ð  What is the total work, WT, done on the box?

 

           WT = Wfr +  WP = -200 J + 300 J = 100 J

 

¢  A disk is accelerated from rest to 60,000 revolutions per minute in 30 s.

 

    ð  What is the angular velocity at the end of 30 s?

 

w = 2p f = (2 p  rad/rev) (60,000 rev/min)(min/60 sec) = 2000p rad/s  or 2p1000 rad/s

 

¢  Assume that the answer to the above question is m rad/sec. What is the average angular acceleration during the stated period?

 

ᾱ = Dw/Dt =  (w - w0)/Dt = (m - 0)/30 = m/30 rad/s2

 

¢  In the following drawing, two disk-shaped wheels of radii RA = 30 cm and RB = 50 cm (indicated by the horizontal and vertical lines from the center), are attached

    to each other on an axle that passes through the center of each. Two forces are acting as shown. Calculate the net torque on this compound wheel due to the

    forces shown.

 

 

We choose counterclockwise as positive, in accordance with convention.

 

tnet = (RB)x(FB ) - (RA)x(FA)  = (.30)x(50)x1 - (0.5)x(50)xcos(30) = 15 - 25x(3)1/2/2        Cosine because of way angle is shown  Fperp to radius

 

¢  A long uniform rod has a mass of 2 kg and a length of 3 m. The axis is through an end. What is the moment of inertia of the rod.

 

(1/3) ML2 = (1/3)(2 kg)(3 m)2 = 6 kg m2

 

¢  A 3 kg sphere is rolling on a frictionless surface with an angular velocity of 4 rad/sec and a translational velocity of 2 m/sec. The moment of inertia of the sphere

    is 2 kg m2. What s the total kinetic energy of the object at a point in time?

 

KEtotal = KErotational + KEtranslational = (1/2)mv2 + (1/2)Iw2 = (1/2)(3)(2)2 + (1/2)(2)(4)2

 

= 6 + 16 = 22

 

¢   A person is washing a car with a hose. Water leaves the hose at a rate of 2.0 kg/s with a speed of 20 m/s. The water is aimed at the side of the car which

    stops it. Assume that there is no splash back of the water.  What is the force exerted by the water on the car?

   

      Take the positive direction to be to the right. Use Newton’s second law in momentum form which is, in words

 

      The rate of change of momentum of an object is equal to the net force applied to it

 

The equation is

 

     FDt = DP

 

When the water hits the car the momentum goes to 0 (Pfinal = 0).

The initial momentum of the water, Pinitial = mv = (2.0 kg/s)(20 m/s) = 40.0 kg m/s.

Since 2.0 kg of water leaves the hose each second, we choose Dt = 1.0 s

 

FDt = DP gives  F = DP/Dt = (Pfinal – Pinitial)/1.0 s = 0 – 40 kg m/s

F = - 40 N  which is the force exerted by the car on the water.  By Newton’s third law, the force of the water on the car is equal to this with opposite sign

 

F = 40 N

 

Section 4: Conservation Laws and Principles

 

Conservation laws are very important in physics; they allow us to solve problems that would be difficult or impossible to solve without them.  It is important, however, to recognize when these laws are applicable before they are used. A number of criteria (conditions that must be met in order for the law to be applicable) are listed below and identified by the characters A through G.

 

Criteria For Use

 

A.   For collisions that are elastic

B.   In a system on which no outside non-zero forces are acting      Note: This is not the same situation as listed in otion K

C.   In an inertial reference frame.

D.   In an inertial reference frame in which there is no net force acting on the object.

E.   When the temperature is not too hot

F.   Always

G.  When only conservative forces are acting

H.  When the net torque acting on it is zero.

J.   When there is no torque acting on it.

K.   When the external forces acting on the system add to zero

M.  When there are no external forces acting on the system

 

¢  For each of the following conservation laws or principles, place the appropriate criteria for its

    use on the adjacent line.

 

    ð  Total energy of a closed system                                         __________   F

 

    ð  Newton's first law of motion                                                __________   D

 

    ð  Total angular momentum of a rotating object.                      __________   H

 

    ð  Total mechanical energy of an isolated system of objects    __________   G

 

    ð  Total kinetic energy of an isolated system of objects           __________   A

 

    ð  Total momentum of an isolated system of objects               __________   K

 

Section 5: Labs

A number of labs, as listed below, were assigned. For each state the objective and conclusion.

 

¢  Centripetal force lab.

 

 

 

To measure the effect of speed on centripetal force. Theoretically, the centripetal force should be directly proportional to the square of the speed. To check this, add a column to your data table for v2. Construct a graph of centripetal force versus v2.

 

¢  Projectile slammed into a target on an air table. After the collisions, the two remained

    attached.

 

 

To verify conservation of momentum in an inelastic collision.

 

 

¢  Ball rolling down different tracks.

 

 

To show that the potential energy for balls on the different tracks is the same because it depends on height, the same for all tracks. All of the potential energy is converted into kinetic energy so the balls should travel about the same distance (and they did).

 

 

Section 6: Demonstrations

A number of demonstrations, as listed below were provided. They are included in the Concepts Demonstrations By Chapter section of my manual. For each, identify the principle or law, or concept that was being illustrated.

Added during Review Exercise: Extra credit if give first and last names of students that conducted the demonstration in class.

 

¢  Rotating rods of equal mass    Amanda Burroughs

 

Since I is given by mr2, the rod with the mass near the center has a lower I if rotated about the center.

If they are rotated about an end, however, the moments of inertia should be about the same.

 

¢  Wheel and chair system      Elora Overbey

 

This is an illustration of conservation of angular momentum.

 

¢  Ball being thrown by one student at another      Ben Berling

 

As Sir Isaac Newton explained, åF = ma = m Dv/Dt

 

which leads to FDt = m Dv =D p     where p is the momentum

 

 FDt is referred to as the impulse.

 

We can see that the impulse is directly related to the time (Dt) over which the force acts.

 

Section 7: Answer the following questions.

 

¢   I discussed and solved a problem in which a bullet struck a target suspended by

    a string. The bullet lodged in the target which then swung up a given distance. I broke the

    problem into two parts.

 

    ]  Why did I break the problem into 2 parts?

 

         Because the same approach did not work for both parts

 

    ]  What law or principle did I use for the first part?

 

         Conservation of momentum since no net outside force was acting on the system.

 

    ]  What law or principle did I use for the second part?

 

         There was a net outside force acting (gravity) so conservation of momentum could not be used.

         Conservation of mechanical energy could be used since the only force acting was conservative (gravity)

 

¢   Define a radian as discussed in class and in the text. Just stating how many are in a circle or giving a relationship between a radian and a degree will receive no

     credit.

 

A radian is the angle subtended by an arc that is the same length as the radius of the circle.

 

¢   A disk is rotating at a constant angular velocity.

 

    ]  Does a point on the rim have radial or tangential acceleration or both? Give clear and specific rationale for your answer.

 

         Radial only.

 

         aradial = rw 2           w is a known constant, w ¹ 0

         atan = r Dw/Dt       Dw = 0 (constant w). So atan = 0

 

    ]  If the disk’s angular velocity increases uniformly, does the point have radial or tangential acceleration or both?  Give clear and specific rationale for your answer.

 

         Both radial and tangential.

 

         aradial = rw 2           w is a known constant, w ¹ 0

         atan = r Dw/Dt       Dw  ¹  0, so atan    ¹ 0

 

 

Section 8: Extra Credit

       

¢  Pictures and biographies of 10 giants in physics are listed on my Physics B home page. Identify the following giants.

 

    ð  He assisted in the development of the atomic bomb and was a member of the panel that investigated the Space Shuttle Challenger disaster. In addition to his

         work in theoretical physics, he has been credited with pioneering the field of quantum computing and introducing the concept of nanotechnology (creation of

         devices at the molecular scale.    ________________________ Richard Feynman

 

    ð  He  was an Italian physicist, mathematician, astronomer, and philosopher who played a major role in the Scientific Revolution.  __________________ 

         Galileo Galilei

 

    ð  He was a German physicist and philosopher who, in 1925, discovered a way to formulate quantum mechanics in terms of matrices.____________________

         Werner Heisenberg

 

    ð  Born in Copenhagen, Denmark. He won the 1922 Nobel prize for physics, chiefly for his work on atomic structure. ___________________ Niels Bohr